" Every group of prime order is cyclic."


 Let G be of prime order p , and let a be an element of G other than the identity.

Consider the cyclic subgroup <a>.
Since a ≠ e , |a| = |<a>| ≥ 2 .

By Lagrange's theorem, |<a>| must divide |G| = p

There are only two numbers dividing a prime number, that is 1 and p itself.
Since |<a>| ≠ 1 , |<a>| = p .

Thus G = <a> , so G is cyclic.